Learning Objectives
2 objectivesBy the end of this note, you should be able to:
- Understand that all physical quantities consist of a numerical magnitude and a unit.
- Make reasonable estimates of physical quantities included within the syllabus.
Structure of a Physical Quantity
Every measurement in physics is a physical quantity, which always consists of two inseparable parts: a numerical magnitude and a unit. The magnitude tells you how much, and the unit tells you of what. Writing one without the other is meaningless in physics.
For example, stating a length as “5” tells you nothing useful, because 5 metres, 5 millimetres, and 5 kilometres describe vastly different physical sizes. The complete quantity must be written as $5 m$, pairing the magnitude with the SI unit.
This rule applies to every quantity in the syllabus, scalar or vector. Mass, time, force, current, and energy must each be expressed with both a numerical value and a recognised unit. In Cambridge 9702 examinations, omitting the unit in a final answer typically loses a mark, even when the arithmetic is correct.
| Element | What it tells you | Example |
|---|---|---|
| Numerical magnitude | The size of the quantity | 5 |
| Unit | The standard of comparison | m |
| Physical quantity | Magnitude × unit | 5 m |
MisconceptionStudents often treat the unit as optional decoration rather than part of the quantity itself. A “bare number” answer is incomplete. The unit defines the physical meaning of the magnitude, so the two must always be written together. Exam cue: always check that every numerical answer carries the correct SI unit.
Examiner InsightCambridge mark schemes routinely penalise missing or wrong units in calculation answers. A correct numerical value with a missing unit often scores zero on that mark. Exam cue: write the unit immediately after the number, even in intermediate steps.
Reasonable Estimates of Physical Quantities
A key skill is the ability to make reasonable estimates of everyday physical quantities to the correct order of magnitude. Examiners test whether you have a realistic feel for the typical size of common physical values, not exact figures.
Estimation requires you to relate unfamiliar quantities to familiar reference values. The mass of an apple is approximately $0.1 kg$, so a bag of ten apples is roughly $1 kg$. A person walking at a steady pace moves at about $1.5 m {s}^{-1}$, which gives a useful benchmark for human-scale speeds.
The table below lists representative estimates that appear in 9702 examinations. Magnitudes within a factor of 2–3 of these values are normally accepted as reasonable.
| Quantity | Reasonable estimate |
|---|---|
| Mass of an adult human | $70 kg$ |
| Mass of an apple | $0.1 kg$ |
| Height of a doorway | $2 m$ |
| Diameter of a human hair | $1\times {10}^{-4} m$ |
| Walking speed | $1.5 m {s}^{-1}$ |
| Speed of a car on a motorway | $30 m {s}^{-1}$ |
| Speed of sound in air | $340 m {s}^{-1}$ |
| Mass of a chicken egg | $0.06 kg$ |
| Volume of a can of drink | $3.3\times {10}^{-4} {m}^{3}$ |
| Density of water | $1000 kg {m}^{-3}$ |
| Atmospheric pressure | $1.0\times {10}^{5} Pa$ |
| Weight of a 1 kg object on Earth | $9.81 N$ |
| Power of a domestic light bulb | $60 W$ |
| Frequency of mains electricity | $50 Hz$ |
| Wavelength of visible light | $5\times {10}^{-7} m$ |
| Period of a heartbeat | $1 s$ |
When estimating an unfamiliar quantity, break the problem into smaller, familiar parts. To estimate the mass of air in a classroom, multiply the room’s volume by the density of air ($kg {m}^{-3}$). This step-by-step decomposition is the technique examiners reward.
Worked Example: Estimating the Mass of Air in a Classroom
A typical classroom measures approximately $8 m$ by $6 m$ by $3 m$. Estimate the mass of air it contains, taking the density of air as $1.2 kg {m}^{-3}$.
Step 1 — Calculate the volume of the room
Equation used
$$V=lwh$$
Given
$$l=8 m$$
$$w=6 m$$
$$h=3 m$$
Substitution:
$$V=8\times 6\times 3$$
$$V=144 {m}^{3}$$
Step 2 — Calculate the mass of air
Equation used: density formula, rearranged for mass.
$$m=\rho V$$
Given
$$\rho =1.2 kg {m}^{-3}$$
$$V=144 {m}^{3}$$
Substitution:
$$m=1.2\times 144$$
$$m=172.8 kg$$
$$m\approx 170 kg (2 s.f.)$$
A typical classroom contains roughly $170 kg$ of air, which is heavier than two adults. This shows that air, despite being invisible, has significant mass on a room-sized scale.
Examiner InsightEstimation questions are marked on order-of-magnitude correctness, not precise values. Answers within a factor of two or three of the expected value usually score full marks. Exam cue: state assumptions clearly, and always check whether the final magnitude looks physically sensible.

QUICK RECAP
Key Points
- A physical quantity = numerical magnitude × unit.
- A bare number without a unit has no physical meaning.
- Cambridge mark schemes penalise missing or incorrect units.
- Mass of an adult ≈ $70 kg$.
- Walking speed ≈ $1.5 m {s}^{-1}$.
- Speed of sound in air ≈ $340 m {s}^{-1}$.
- Density of water = $1000 kg {m}^{-3}$.
- Atmospheric pressure ≈ $1.0\times {10}^{5} Pa$.
- Wavelength of visible light ≈ $5\times {10}^{-7} m$.
- Estimation questions are marked by order of magnitude.
- Break large estimations into familiar smaller parts.
- Always state assumptions clearly when estimating.
CAN I…? PROGRESS CHECK
Self-Assessment
- Can I state that a physical quantity consists of a magnitude and a unit?
- Can I explain why a measurement without a unit is incomplete?
- Can I recall typical magnitudes for mass, length, speed, density, and pressure of everyday objects?
- Can I estimate the mass of air in a room using density and volume?
- Can I judge whether a given estimate is reasonable for a familiar quantity?
- Can I break a complex estimation into simpler, familiar steps?
- Can I clearly state any assumptions made during an estimation?