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Periodicity melting points and ionisation energies

Learning Objectives

6 objectives

By the end of this note, you should be able to:

  • Represent data graphically for elements 1–36, including logarithms of first ionisation energies.
  • Explain the meaning of the term periodic property using graphical data.
  • Explain trends in melting and boiling temperatures across Periods 2 and 3.
  • Explain the general increase in first ionisation energy across Periods 2 and 3.
  • Explain specific dips in ionisation energy across Periods 2 and 3.
  • Explain the decrease in first ionisation energy down a group.

Graphical Data and Periodic Properties

A periodic property is any physical property whose value rises and falls in a repeating pattern when elements are plotted in order of increasing atomic number.

Plotting properties such as melting temperature, atomic radius, or first ionisation energy against atomic number for elements 1 to 36 reveals clear repeating peaks and troughs across each period. This repetition is what defines a property as “periodic”, because the pattern recurs every time a new period begins.

First ionisation energies for elements 1 to 36 span a very large numerical range, from a few hundred to several thousand kJ mol⁻¹. Plotting raw values compresses the lower numbers and obscures fine detail in the early periods.

Taking the logarithm of the first ionisation energy before plotting reduces the spread, so the periodic pattern becomes visually clearer and small dips within each period are easier to identify.

Graph of log first ionisation energy against atomic number for elements 1 to 36, peaking at noble gases and troughing at Group 1 metals across Periods 2 to 4.
Examiner InsightWhen asked to define a periodic property, state explicitly that the property repeats at regular intervals across the periodic table. A vague answer such as “changes across a period” does not earn the mark.
Exam TipUse the word “repeats” or “repeating pattern” to secure the mark.

Trends in Melting Points and Ionisation Energies

Across Periods 2 and 3, melting temperatures, boiling temperatures, and ionisation energies all change in patterns that depend directly on structure, bonding, and electron configuration.

Melting and boiling temperatures across Period 3 rise from sodium to silicon, then fall sharply, because the type of structure and bonding changes across the period. Period 2 follows the same logic with lithium to carbon rising, then a sharp fall to nitrogen, oxygen, fluorine, and neon.

The table below summarises the structure and bonding for each Period 3 element and explains why its melting temperature is high or low.

Element Structure and bonding Melting temperature Reason
Na Giant metallic, 1 delocalised e⁻ per atom Low (relative to Mg, Al) Weak metallic bonding; only 1 outer electron delocalised
Mg Giant metallic, 2 delocalised e⁻ per atom Higher than Na Stronger metallic bonding; more delocalised electrons; smaller ion
Al Giant metallic, 3 delocalised e⁻ per atom Higher than Mg Even stronger metallic bonding; 3 delocalised electrons; smaller ion
Si Giant covalent (macromolecular) Very high (highest in Period 3) Many strong covalent bonds must be broken throughout the lattice
P (P₄) Simple molecular Low Only weak London forces between P₄ molecules
S (S₈) Simple molecular Higher than P, Cl Larger S₈ molecules give stronger London forces than P₄
Cl (Cl₂) Simple molecular Very low Small Cl₂ molecules give weak London forces
Ar Monatomic Lowest Weakest London forces between single atoms

Period 2 follows the same structural logic: Li, Be metallic; B, C giant covalent (with C giving the highest melting point); N₂, O₂, F₂, Ne simple molecular or monatomic with low melting points.

Melting point trend across Period 3 rising from Na to Al, peaking sharply at giant covalent silicon, then dropping for simple molecular P, S, Cl and Ar.

The first ionisation energy is the energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions.

The defining equation is shown below:

$$X(g)\to {X}^{+}(g)+{e}^{-}$$

Across Periods 2 and 3, first ionisation energy generally increases because nuclear charge increases while electrons are added to the same main shell. Shielding stays roughly the same, so the outer electron is held more strongly and harder to remove.

Two specific dips break this general increase in each period.

The first dip occurs between Group 2 and Group 3 (Be → B in Period 2; Mg → Al in Period 3). The outer electron in Group 3 is in a 2p (or 3p) orbital, which is at a slightly higher energy than the 2s (or 3s) orbital. This electron is therefore easier to remove despite the higher nuclear charge.

The second dip occurs between Group 5 and Group 6 (N → O in Period 2; P → S in Period 3). In Group 5 every p orbital holds one electron, but in Group 6 one p orbital holds a paired electron. The two paired electrons repel each other, so one is more easily removed.

Down a group, first ionisation energy decreases because three effects combine. The outer electron occupies a shell further from the nucleus. More inner shells provide greater shielding from the nuclear charge. These two effects outweigh the increase in nuclear charge, so the outer electron is held less strongly.

First ionisation energy graph across Periods 2 and 3 showing the general increase with dips at Group 13 and Group 16 from sub-shell and p-electron pairing effects.
MisconceptionThe dip from N to O is not because oxygen has “more electrons” or “a higher nuclear charge”. It is because pairing two electrons in the same 2p orbital introduces repulsion, lowering the energy needed to remove one of those paired electrons.
Exam TipState “paired electrons in the same p orbital repel” to secure the mark.

Worked Example: Comparing First Ionisation Energies

Scenario

The first ionisation energies of three Period 3 elements are 738, 578, and 786 kJ mol⁻¹. Identify each element and explain the order.

Step 1 — Identify the elements. The three values correspond to Mg (738), Al (578), and Si (786) in Period 3.

Step 2 — Compare Mg and Al. Across Period 3, ionisation energy generally increases, but Al is lower than Mg. The outer electron of Al is in a 3p orbital, which is higher in energy than the 3s orbital of Mg. Therefore the 3p electron in Al is easier to remove despite Al having a higher nuclear charge.

Step 3 — Compare Al and Si. Both have outer electrons in 3p orbitals. Si has a higher nuclear charge than Al with the same shielding. Therefore the 3p electron in Si is held more strongly, giving a higher first ionisation energy.

Interpretation

The order Al (578) < Mg (738) < Si (786) shows the general increase across the period, broken by the s-to-p sub-shell dip between Group 2 and Group 3.

QUICK RECAP

Key Points

  • A periodic property repeats with increasing atomic number.
  • Log scales compress wide-ranging data such as ionisation energies.
  • Noble gases give peaks; Group 1 metals give troughs.
  • Period 3 metals: Na < Mg < Al in melting temperature.
  • More delocalised electrons mean stronger metallic bonding.
  • Silicon has the highest melting point (giant covalent).
  • P₄, S₈, Cl₂, Ar are simple molecular or monatomic with low mp.
  • First ionisation energy: X(g) → X⁺(g) + e⁻.
  • IE increases across a period: rising nuclear charge, similar shielding.
  • IE drops at Group 3: outer electron in higher-energy p orbital.
  • IE drops at Group 6: paired p electrons repel each other.
  • IE decreases down a group: larger atom, more shielding.
  • Always state structure and bonding when explaining melting points.
  • Always link IE trends to electron configuration.

CAN I…? PROGRESS CHECK

Self-Assessment

  • Can I define a periodic property and recognise one from a graph?
  • Can I explain why log(ionisation energy) graphs are used for elements 1–36?
  • Can I describe the melting temperature trend across Period 3?
  • Can I link each Period 3 element’s melting point to its bonding?
  • Can I write the equation for the first ionisation energy of any element?
  • Can I explain the general increase in first IE across a period?
  • Can I explain the IE dip from Group 2 to Group 3?
  • Can I explain the IE dip from Group 5 to Group 6?
  • Can I explain why first IE decreases down a group?
  • Can I compare first IE values numerically for two elements and justify the order?
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